Starting the database server with -c %%

1) If I run dbsrv12.exe -c 30%% then

a) For 12.0.1.3537 - OK

    2: -c

    3: 30%%

    ...

    SQL Anywhere Network Server Version 12.0.1.3537

    ...

    Running Windows 7 Build 7601 Service Pack 1 on X86_64

    Server built for X86_64 processor architecture

    2511152K of memory used for caching

    Minimum cache size: 2511152K, maximum cache size: 7529760K

b) For 12.0.1.4178: Invalid database server command line error

2) If I run dbsrv12.exe -c 30% then
a) For 12.0.1.3537 - OK
b) For 12.0.1.4178 - OK

    2: -c

    3: 30%

    ...

    SQL Anywhere Network Server Version 12.0.1.4178

    ...

    Running Windows 7 Build 7601 Service Pack 1 on X86_64

    Server built for X86_64 processor architecture

    2511152K of memory used for caching

    Minimum cache size: 2511152K, maximum cache size: 7529760K

Is it bug? For 12.0.1.3537 or for 12.0.1.4178 ?

sa-12 command-line

asked 30 Mar '15, 07:56

Ilia63
1.2k●49●55●78
accept rate: 44%

edited 30 Mar '15, 11:18

Mark Culp
24.8k●9●139●295

flat view

One Answer:

active answers oldest answers newest answers popular answers

You want one "%" sign to make it to the server. If the server is invoked from a shell (cmd.exe on Windows), "%%" gets converted to "%" by the shell because "%" is used for environment variable substitutions. You appear to be invoking the server without using a shell so you only want -c 30%.

To avoid issues with shells and %, you could just use -c 30p.

-john.

permanent link

answered 30 Mar '15, 08:05

John Smirnios
11.4k●3●94●154
accept rate: 38%

Fortunately, "p" in this case doesn't stand for "petabytes." That would be a big cache.

(02 Apr '15, 14:41) Phil Mitchell

flat view

Your answer

toggle preview

community wiki:

Follow this question

By Email:

Once you sign in you will be able to subscribe for any updates here

By RSS:

Answers

Answers and Comments

Markdown Basics

*italic* or _italic_
**bold** or __bold__
link:[text](http://url.com/ "title")
image?![alt text](/path/img.jpg "title")
numbered list: 1. Foo 2. Bar
to add a line break simply add two spaces to where you would like the new line to be.
basic HTML tags are also supported

learn more about Markdown

Question tags:

sa-12 ×438
command-line ×5

question asked: 30 Mar '15, 07:56

question was seen: 1,482 times

last updated: 02 Apr '15, 14:41

SAP SQL Anywhere

Starting the database server with -c %%

Follow this question

Related questions