1) If I run dbsrv12.exe -c 30%% then a) For 12.0.1.3537 - OK 2: -cb) For 12.0.1.4178: Invalid database server command line error 2) If I run dbsrv12.exe -c 30% then 2: -cIs it bug? For 12.0.1.3537 or for 12.0.1.4178 ? |
You want one "%" sign to make it to the server. If the server is invoked from a shell (cmd.exe on Windows), "%%" gets converted to "%" by the shell because "%" is used for environment variable substitutions. You appear to be invoking the server without using a shell so you only want -c 30%. To avoid issues with shells and %, you could just use -c 30p. -john. 2
Fortunately, "p" in this case doesn't stand for "petabytes." That would be a big cache.
(02 Apr '15, 14:41)
Phil Mitchell
|