How to display the result of where clause next App.app_num

-1

I am trying to get all the applications which was updated before 5 business day

I am able to to get all the applications by using the following where clause calculation.

Also, I would like to display the number of day it was last updated.

SELECT A.APP_NUM
FROM Application A,

WHERE
((Dayofyear(CURRENT_DATE) - Dayofyear(cast (A.LAST_UPDATE_TIMESTAMP as DATE))) + 1) - ((Week(CURRENT_DATE) - Week(cast (LAST_UPDATE_TIMESTAMP as DATE))) * 2) - (case when DAYOFWEEK(CURRENT_DATE) > 6 then 1 else 0 end) - (case when DAYOFWEEK(cast (LAST_UPDATE_TIMESTAMP as DATE)) < 2 then 1 else 0 end) >5

embedded-sql mysql

asked 04 Mar '14, 11:32

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accept rate: 0%

This forum is about SAP SQL Anywhere not MySQL - you will probably do better on Stack Overflow or a dedicated MySQL forum.

(05 Mar '14, 05:37) Justin Willey

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Question tags:

mysql ×16
embedded-sql ×9

question asked: 04 Mar '14, 11:32

question was seen: 9,356 times

last updated: 05 Mar '14, 05:37

SAP SQL Anywhere

How to display the result of where clause next App.app_num

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